Which of the following are correct matches?(a | vedclass

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(D) The stability of oxoanions increases with the number of oxygen atoms due to resonance stabilization. Thus,$ClO_4^- > ClO_3^- > ClO_2^- > ClO^-$ is

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All of these

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(D) The stability of oxoanions increases with the number of oxygen atoms due to resonance stabilization. Thus,$ClO_4^- > ClO_3^- > ClO_2^- > ClO^-$ is correct.$(b)$ The bond energy order for halogens is $Cl_2 > Br_2 > F_2 > I_2$. $F_2$ has an anomalously low bond energy due to inter-electronic repulsions between lone pairs. Thus,this is correct.$(c)$ The bond angle order is $OF_2 (103^\circ) $(d)$ Reducing power increases as the size of the halide ion increases,making it easier to lose electrons. Thus,$I^- > Br^- > Cl^-$ is correct.Since all statements are correct,the answer is 'All of these'.

Which of the following are correct matches?
$(a)$ $ClO_4^- > ClO_3^- > ClO_2^- > ClO^-$ (Stability order)
$(b)$ $Cl_2 > Br_2 > F_2 > I_2$ (Bond energy)
$(c)$ $OF_2 < OH_2 < OCl_2$ (Bond angle)
$(d)$ $I^- > Br^- > Cl^-$ (Reducing power)

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Which of the following are correct matches?$(a)$ $ClO_4^- > ClO_3^- > ClO_2^- > ClO^-$ (Stability order)$(b)$ $Cl_2 > Br_2 > F_2 > I_2$ (Bond energy)$(c)$ $OF_2 < OH_2 < OCl_2$ (Bond angle)$(d)$ $I^- > Br^- > Cl^-$ (Reducing power)